Bridge:
Mohamed wants to the dimensions for the arch
a) Which term in the equation defines the horizontal axis?
x^2/182.25
b) Write a comparative statement to show whether the major axis of the arch is horizontal or vertical
horizontal, because value under x is bigger which refer to a horizontal drawing.
c) Mohamed says that the width of the bridge is 13.5 feet. Is he correct? Explain.
no, 13.5 is half the direction 50 multiply by 2, 13.5x2=27
d) Write an expression for the height of the bridge.
b^2=132.25
b=11.5 AU
Salim notes that this bridge is hardly high enough to pass under while standing up in a moderate-size boat. If he were to build a bridge, it would be at least 1.3 times as wide and twice as high.
a) Find the vertices and co-vertices of Salim’s bridge design.
2b=1.3x2x13.5=35.1
b=35.1/2=17.55
2a=2x2x11.5=46
a=46/2=23
vertices= (0,23) (0,-23) co-vertices (17.55,0) (-17.55,0)
b) Write an equation for the design of Salim’s bridge using his minimum dimensions.
(x-h)^2/b^2+(y-k)^2/a^2=1
(x-0)^2/(17.55)^2+(y-0)^2/(23)^2=1
(x)^2/(308.0025)+(y)^2/(529)=1
a) Which term in the equation defines the horizontal axis?
x^2/182.25
b) Write a comparative statement to show whether the major axis of the arch is horizontal or vertical
horizontal, because value under x is bigger which refer to a horizontal drawing.
c) Mohamed says that the width of the bridge is 13.5 feet. Is he correct? Explain.
no, 13.5 is half the direction 50 multiply by 2, 13.5x2=27
d) Write an expression for the height of the bridge.
b^2=132.25
b=11.5 AU
Salim notes that this bridge is hardly high enough to pass under while standing up in a moderate-size boat. If he were to build a bridge, it would be at least 1.3 times as wide and twice as high.
a) Find the vertices and co-vertices of Salim’s bridge design.
2b=1.3x2x13.5=35.1
b=35.1/2=17.55
2a=2x2x11.5=46
a=46/2=23
vertices= (0,23) (0,-23) co-vertices (17.55,0) (-17.55,0)
b) Write an equation for the design of Salim’s bridge using his minimum dimensions.
(x-h)^2/b^2+(y-k)^2/a^2=1
(x-0)^2/(17.55)^2+(y-0)^2/(23)^2=1
(x)^2/(308.0025)+(y)^2/(529)=1