Application:
i. Find an equation of the parabola.
vertex: (0,0) latus rectum: 10 a=1/10 ii. Find the diameter of the opening |CD|, 11 cm from the vertex. 11/0.1=1/10y^2/0.1 y^2=110 y=⎷110 C=(11,⎷110) D=(11,-⎷110) distance(CD) =⎷(y2-y1)^2+(x2-x1)^2 =⎷(⎷110 - -⎷110)^2)+ (11-11)^2 CD=⎷440+0 =2⎷110 |
x=a(y-k)^2+h x=1/10(y)^2+0 x=1/10(y)^2 |